Mastering Properties of Waves

CSEC Physics: Waves & Energy

Essential Understanding: Waves are a method of transferring energy from one place to another without transferring matter. Whether it’s the sound of music, the light from the sun, or the ripples in a pond, understanding Amplitude, Wavelength, and Frequency is key to mastering the physical world.

🔑 Key Skill: Using \( v = f \lambda \)
📈 Exam Focus: Identifying Crests, Troughs, Compressions
🎯 Concept: Transverse vs. Longitudinal motion

Core Concepts

📈

Transverse Waves

Definition: Waves where the particle vibration is perpendicular (at 90°) to the direction of energy transfer.

Examples: Light waves, Water ripples, Waves on a string.

Key Terms: Crest (peak), Trough (valley).

↔️

Longitudinal Waves

Definition: Waves where the particle vibration is parallel to the direction of energy transfer.

Examples: Sound waves, Primary (P) seismic waves.

Key Terms: Compression (high pressure), Rarefaction (low pressure).

📏

Amplitude

Definition: The maximum displacement of a particle from its rest position.

Physical Meaning: Relates to the energy and loudness (sound) or brightness (light) of the wave.

Symbol: \( A \) (Unit: meters, m)

↔️

Wavelength (\( \lambda \))

Definition: The distance between two consecutive similar points in phase (e.g., crest to crest, compression to compression).

Unit: meters (m).

⏱️

Frequency (\( f \))

Definition: The number of complete waves passing a point per second.

Unit: Hertz (Hz). \( 1 \text{ Hz} = 1 \text{ vibration/s} \).

Related: Period (\( T \)) is the time for one wave: \( T = \frac{1}{f} \).

The Wave Equation

This is the most important formula in this topic. It connects the speed of the wave to its frequency and wavelength.

\[ v = f \lambda \]
  • \( v \): Wave speed (m/s)
  • \( f \): Frequency (Hz)
  • \( \lambda \): Wavelength (m)

Interactive Wave Lab

🎢

Transverse Wave Simulator

Objective: Observe how changing Amplitude and Frequency affects the shape of a transverse wave. Notice that the green dots (particles) only move up and down, while the wave moves right.

Current Amplitude

50 px

Current Frequency

2.0 Hz

Displacement-Distance vs. Displacement-Time

CSEC exams often test your ability to distinguish between a “snapshot” of a wave and the movement of a single particle. The chart below compares these two critical perspectives.

Analysis: Blue Line (Displacement-Distance): Shows the shape of the wave at one instant in time. The distance between peaks is the Wavelength.
Orange Line (Displacement-Time): Shows the movement of one single point over time. The distance between peaks is the Period (\( T \)).

🧮

Worked Example: Calculating Speed

A water wave has a frequency of 4 Hz and a wavelength of 0.5 m. Calculate the speed of the wave.

1
Identify Variables: Frequency \( f = 4 \text{ Hz} \), Wavelength \( \lambda = 0.5 \text{ m} \).
2
Select Formula: We need to find \( v \), so use the Wave Equation: \( v = f \lambda \).
3
Substitute and Calculate: \( v = 4 \times 0.5 \).
4
Final Answer: \( v = 2 \, \text{m/s} \).

Key Examination Insights

Common Mistakes

  • Confusing the Period (\( T \)) with Frequency. Remember \( f = \frac{1}{T} \).
  • Forgetting unit conversions: kHz to Hz (x 1000) or cm to m ( / 100).
  • Assuming particles move along with the wave. In all mechanical waves, matter only oscillates; energy moves forward.

Success Strategies

  • For longitudinal diagrams, label Compressions (C) where particles are close and Rarefactions (R) where they are far apart.
  • When given a diagram, count the number of cycles carefully to find wavelength.
  • Always check if the wave is “Frozen” (Distance graph) or “Moving” (Time graph).

CSEC Practice Arena

Test Your Understanding

1
Which of the following units is used to measure Frequency?
Meters (m)
Meters per second (m/s)
Seconds (s)
Hertz (Hz)
Explanation: Frequency measures the number of oscillations per second. The unit is named after Heinrich Hertz and is abbreviated as Hz.
2
A wave has a speed of 300 m/s and a frequency of 150 Hz. Calculate the wavelength.
450 m
0.5 m
2 m
45,000 m
Solution: Rearrange the wave equation: \( \lambda = \frac{v}{f} \).
\( \lambda = \frac{300}{150} = 2 \, \text{m} \).
3
In a sound wave (longitudinal), which region represents the lowest pressure?
Compression
Rarefaction
Crest
Trough
Explanation: Rarefactions are areas where particles are spread far apart, resulting in lower density and lower pressure. Compressions are high pressure.
🎯

CSEC Examination Mastery Tip

Graph Interpretation: In multiple-choice questions, you will often be shown a graph.

  • Look at the X-axis label first.
    • If it says Distance (m): You are looking at the wave shape. The peak-to-peak distance is Wavelength (\( \lambda \)).
    • If it says Time (s): You are looking at one particle oscillating. The peak-to-peak distance is Period (\( T \)).
  • Once you identify the x-axis, you can instantly calculate Frequency (\( f = 1/T \)) or confirm Wavelength.
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