Mean, Median, and Mode

Measures of Central Tendency

Essential Understanding: These three measures help us find the “center” or “typical value” of a data set. Each measure has its own purpose and is useful in different situations.

Mean: The average
Median: The middle value
Mode: The most frequent

The Three Averages

\(\bar{x}\)

Mean (Arithmetic Average)

Definition: The sum of all values divided by the number of values.

\[ \bar{x} = \frac{\sum x}{n} \]

When to use: When all data values are important and there are no extreme outliers.

Median (Middle Value)

Definition: The middle value when data is arranged in order.

Finding it:

  • Odd \(n\): Middle value
  • Even \(n\): Average of two middle values

When to use: When data has outliers or is skewed.

Mode (Most Common)

Definition: The value that appears most frequently.

Special cases:

  • No mode: All values appear equally
  • Bimodal: Two modes
  • Multimodal: More than two modes

When to use: For categorical data or finding the most popular item.

Interactive Calculator

Data Analyzer

Enter your data values separated by commas and see the mean, median, and mode calculated instantly!

Mean

Median

Mode

Step-by-Step Examples

Example 1: Finding Mean, Median, and Mode

Data: The ages of 7 students are: 14, 15, 13, 15, 16, 15, 14

Finding the Mean:

1
Add all values: \( 14 + 15 + 13 + 15 + 16 + 15 + 14 = 102 \)
2
Divide by count: \( \bar{x} = \frac{102}{7} = 14.57 \) (to 2 d.p.)

Finding the Median:

1
Arrange in order: 13, 14, 14, 15, 15, 15, 16
2
Find middle position: \( \frac{7+1}{2} = 4 \)th value
3
Median = 15 (the 4th value)

Finding the Mode:

1
Count each value: 13 appears 1 time, 14 appears 2 times, 15 appears 3 times, 16 appears 1 time
2
Mode = 15 (appears most often)
Example 2: Even Number of Values (Finding Median)

Data: Test scores: 72, 85, 63, 91, 78, 84

1
Arrange in order: 63, 72, 78, 84, 85, 91
2
With 6 values (even), find the two middle values: 3rd and 4th positions
3
Middle values are 78 and 84
4
Median = \( \frac{78 + 84}{2} = \frac{162}{2} = 81 \)

Mean from a Frequency Table

Formula for Grouped Data

When data is given in a frequency table:

\[ \bar{x} = \frac{\sum fx}{\sum f} \]

where \(f\) = frequency and \(x\) = data value (or class midpoint for grouped data)

Example 3: Mean from Frequency Table

Question: Find the mean number of goals scored.

Goals (\(x\)) Frequency (\(f\)) \(fx\)
030
177
2510
3412
414
Total \(\sum f = 20\) \(\sum fx = 33\)

Solution:

\[ \bar{x} = \frac{\sum fx}{\sum f} = \frac{33}{20} = 1.65 \text{ goals} \]

When to Use Each Measure

Measure Best Used When Avoid When
Mean Data is symmetrical with no outliers Data has extreme values (outliers)
Median Data is skewed or has outliers You need to use all data values in calculations
Mode Data is categorical or you want the most common value All values appear with equal frequency

The Effect of Outliers

Example: Salaries at a small company: $30,000, $35,000, $32,000, $28,000, $500,000

  • Mean: \(\frac{625,000}{5} = \$125,000\) – Heavily affected by the CEO’s salary!
  • Median: $32,000 – A much better representation of a “typical” salary

This is why median household income is often reported instead of mean income.

CSEC Practice Questions

Test Your Understanding

1
Find the mean of: 4, 7, 9, 5, 10
5
7
9
35
Solution: \(\bar{x} = \frac{4+7+9+5+10}{5} = \frac{35}{5} = 7\)
2
Find the median of: 12, 5, 8, 3, 9, 7, 15
7
8
8.5
9
Solution:
Sorted: 3, 5, 7, 8, 9, 12, 15
7 values, so median is the 4th value = 8
3
The mode of the data set 2, 5, 3, 5, 7, 5, 8 is:
3
5
7
35
Solution: 5 appears 3 times (more than any other value), so the mode is 5.
4
The mean of 5 numbers is 12. If four of the numbers are 10, 15, 8, and 14, find the fifth number.
12
11
13
47
Solution:
Sum of all 5 numbers = Mean × Count = 12 × 5 = 60
Sum of known numbers = 10 + 15 + 8 + 14 = 47
Fifth number = 60 – 47 = 13

Key Points to Remember

  • Mean = \(\frac{\text{Sum of values}}{\text{Number of values}} = \frac{\sum x}{n}\)
  • Median = Middle value when data is ordered (average of two middle values if even count)
  • Mode = Most frequently occurring value (can have no mode, or multiple modes)
  • For frequency tables: Mean = \(\frac{\sum fx}{\sum f}\)
  • Outliers affect the mean but not the median
CSEC Examination Tips
  • Always show your working – write out the sum and division for mean
  • For median: First sort the data, then find the middle position
  • For grouped data: Use class midpoints and the \(\frac{\sum fx}{\sum f}\) formula
  • Check your answer: The mean should be between the smallest and largest values
  • Read carefully: Questions may ask for the “most appropriate” average – consider outliers!
[/raw]
Scroll to Top