How to Solve Half-Life Calculation Problems
CSEC Physics: Master the Calculations
Essential Understanding: Half-life problems involve finding one of three quantities: remaining amount, original amount, or time elapsed. The key is to first determine how many half-lives have passed, then apply the halving pattern. This article provides step-by-step strategies and worked examples for all types of half-life calculations.
The Three Types of Half-Life Problems
Every half-life problem involves finding one of these three quantities. Learn to identify which type you're dealing with:
📉 Type 1: Find Remaining Amount
Given: Original amount (m₀), half-life (T½), time (t)
Find: Remaining amount (m)
Example: "A sample has 100g. After 3 half-lives, how much remains?"
📅 Type 2: Find Time Elapsed
Given: Original amount (m₀), remaining amount (m), half-life (T½)
Find: Time (t)
Example: "50g decays to 6.25g. How much time passed?"
🔢 Type 3: Find Original Amount
Given: Remaining amount (m), half-life (T½), time (t)
Find: Original amount (m₀)
Example: "After 2 half-lives, 25g remains. What was the original mass?"
The Universal Formula
All half-life calculations use this fundamental formula:
Where:
- m = remaining mass (or activity)
- m₀ = original mass (or initial activity)
- n = number of half-lives passed = t ÷ T½
- t = time elapsed
- T½ = half-life
Step-by-Step Method
- Identify the knowns: Write down what you know (m₀, m, t, T½)
- Identify what you're solving for: Is it m, m₀, or t?
- Find the number of half-lives (n): n = t ÷ T½ (if you know t and T½)
- Apply the formula: Use m = m₀ × (½)ⁿ or rearrange as needed
- Calculate and verify: Check if your answer makes sense (remaining < original for decay)
Worked Examples
Example 1: Finding Remaining Mass
Problem: A radioactive sample has an initial mass of 80 g. The half-life is 5 years. What mass remains after 15 years?
Step 1: Identify knowns
m₀ = 80 g, T½ = 5 years, t = 15 years
Step 2: Calculate number of half-lives
n = t ÷ T½ = 15 ÷ 5 = 3 half-lives
Step 3: Apply the formula
m = m₀ × (½)ⁿ = 80 × (½)³
m = 80 × ⅛ = 10 g
Answer: 10 g remains
Example 2: Finding Number of Half-Lives
Problem: A sample decays from 200 g to 25 g. How many half-lives passed?
Step 1: Identify the pattern
200 g → 100 g (1 half-life) → 50 g (2 half-lives) → 25 g (3 half-lives)
Step 2: Verify with formula
m = m₀ × (½)ⁿ
25 = 200 × (½)ⁿ
(½)ⁿ = 25/200 = 1/8 = (½)³
Therefore n = 3
Answer: 3 half-lives passed
Example 3: Finding Time Elapsed
Problem: A sample has a half-life of 12 hours. If the activity drops from 800 Bq to 100 Bq, how much time has passed?
Step 1: Find how many half-lives
800 → 400 (1) → 200 (2) → 100 (3)
n = 3 half-lives
Step 2: Calculate time
t = n × T½ = 3 × 12 = 36 hours
Answer: 36 hours have passed
Example 4: Finding Original Mass
Problem: After 2 half-lives, a radioactive sample has a mass of 30 g. What was the original mass?
Step 1: Work backwards
After 2 half-lives: 30 g represents ¼ of original
Step 2: Calculate original mass
m₀ = m ÷ (½)ⁿ = 30 ÷ (¼) = 30 × 4 = 120 g
Alternative method:
m = m₀ × (½)ⁿ
30 = m₀ × (½)²
30 = m₀ × ¼
m₀ = 30 × 4 = 120 g
Answer: Original mass was 120 g
Example 5: Mixed Problem
Problem: A sample of iodine-131 (half-life = 8 days) has an initial activity of 1600 Bq. After 24 days, what is the remaining activity?
Step 1: Calculate number of half-lives
n = t ÷ T½ = 24 ÷ 8 = 3 half-lives
Step 2: Apply formula
A = A₀ × (½)ⁿ
A = 1600 × (½)³
A = 1600 × ⅛ = 200 Bq
Answer: Remaining activity is 200 Bq
🧮 Interactive Half-Life Calculator
Enter your values to calculate the missing quantity. The visualizer shows how the mass changes with each half-life!
Quick Reference Table
Memorize this pattern to quickly solve problems without calculations:
| Half-Lives Passed | Fraction Remaining | Percentage Remaining | Decayed |
|---|---|---|---|
| 0 | 1/1 | 100% | 0% |
| 1 | 1/2 | 50% | 50% |
| 2 | 1/4 | 25% | 75% |
| 3 | 1/8 | 12.5% | 87.5% |
| 4 | 1/16 | 6.25% | 93.75% |
| 5 | 1/32 | 3.125% | 96.875% |
| 6 | 1/64 | 1.56% | 98.44% |
| 7 | 1/128 | 0.78% | 99.22% |
| 8 | 1/256 | 0.39% | 99.61% |
Practice Problems
Practice 1: Carbon Dating Application
Problem: A wooden artifact from an ancient burial site has a Carbon-14 activity of 25% of a living tree. Carbon-14 has a half-life of 5730 years. How old is the artifact?
Solution:
25% remaining = 1/4 remaining
1/4 = (½)², so 2 half-lives have passed
Age = 2 × 5730 = 11,460 years
Answer: The artifact is approximately 11,460 years old.
Practice 2: Medical Application
Problem: A patient is given a radioactive tracer with Technetium-99m (half-life = 6 hours). The initial activity is 800 mCi. What will be the activity after 24 hours?
Solution:
n = 24 ÷ 6 = 4 half-lives
After 4 half-lives: (½)⁴ = 1/16 remains
Activity = 800 × 1/16 = 50 mCi
Answer: Activity will be 50 mCi after 24 hours.
Summary: Key Takeaways
- Identify the type of problem first: Are you finding remaining amount, original amount, or time?
- Find the number of half-lives (n) by dividing time by half-life: n = t ÷ T½
- Use the formula m = m₀ × (½)ⁿ and rearrange as needed for different unknowns
- Work backwards when finding original mass: multiply remaining mass by 2ⁿ
- Check your answer - remaining mass should always be less than original mass for decay problems
- Memorize the pattern of fractions: ½, ¼, ⅛, 1/16 for quick mental calculations
